Teladan Soal Luas Dan Keliling Bulat Beserta Jawabannya

Lingkaran ialah himpunan semua titik yang membentuk lengkungan tertutup dimana berjarak sama dari suatu titik tetap. Dalam hal ini titik tetap lingkara tersebut kita namakan pusat lingkaran.

Mengenal Bagian-Bagian/Unsur-Unsur Lingkaran

Rumus mencari luas bulat

L = π x r x r atau L = π x r²

Keterangan

L yakni luas bundar
π adalah konstanta yang setara dengan 3,14 atau
22 / 7
r ialah jari-jari lingkaran

Rumus mencari Keliling bulat

L = 2 x π x r atau L = π x d

Keterangan

L ialah luas bundar
π ialah konstanta yang setara dengan 3,14 atau
22 / 7
r yaitu jari-jari bulat
d yakni diameter lingkaran, d = 2xr

Contoh Soal Luas dan Keliling LingkaranSoal No.1 Sebuah lingkaran mempunyai jari-jari sebesar 14 cm. Tentukan luas lingkaran tersebut ?
A. 154 cm²
B. 512 cm²
C. 654 cm²
D. 616 cm² Pembahasan
L = π x r x r
L = 22 / 7 x 14 x 14
L = 616 cm²
Jawab : D Soal No.2 Sebuah roda sepeda yang berupa bulat memiliki diameter sebesar 14 cm. Maka luas dan keliling roda tersebut yakni ?
A. Luas = 154 cm² dan Keliling = 44 cm
B. Luas = 512 cm² dan Keliling = 44 cm
C. Luas = 654 cm² dan Keliling = 64 cm
D. Luas = 616 cm² dan Keliling = 84 cm Pembahasan
d = 14 cm
r = 1 / 2 x 14 = 7 cm Untuk Luas Lingkaran
L = 22 / 7 x r x r
L = 22 / 7 x 7 x 7
L = 154 cm² Untuk Keliling Lingkaran
K = π x d
K = 22 / 7 x d
K = 22 / 7 x 14
K = 44 cm Jawab : A Soal No.3 Pak Andi memiliki suatu kendaraan beroda empat yang panjang jari-jari ban kendaraan beroda empat tersebut sebesar 21 cm. Saat kendaraan beroda empat tersebut berjalan, ban mobil tersebut berputar sebanyak 200 kali. Berapakah jarak yang ditempuh kendaraan beroda empat tersebut ?
A. 265 m
B. 412 m
C. 264 m
D. 178 m Pembahasan K = 2 x π x r
K = 2 x

22 / 7

x 21
K = 132 cm

Jarak yang ditempuh ketika ban mobil berputar 200 kali :
Jarak = Keliling × Banyak putaran
Jarak = 132 × 200
Jarak = 26400 cm
Jarak = 264 m

Jawab : C

Soal No.4 Sebuah bundar mempunyai keliling sebesar 88 cm. Berapakah nilai jari-jari bundar tersebut ?
A. 9 cm
B. 21 cm
C. 14 cm
D. 7 cm Pembahasan K = π x d
88 =

22 / 7

x d
d =

88 x 7 / 22

d = 28 cm

Jari-jari bulat adalah :
r =

1 / 2

x d
r =

1 / 2

x 28
r = 14 cm

Jawab : C

Soal No.5 Sebuah bundar mempunyai luas 3850 cm². Maka panjang diameternya yakni….?
A. 70 cm
B. 35 cm
C. 105 cm
D. 7 cm Pembahasan
L = π x r²
3850 = 22 / 7 x r²
22r² = 3850 x 7
22r² = 26950
r² = 26950 / 7 r² = 1225
r = √1225 = 35 cm Untuk mencari diameter :
d = 2 x r
d = 2 x 35
d = 70 cm Jawab : A Soal No.6 Sebuah bundar bewarna biru berada dalam persegi. Jika panjang segi persegi tersebut yaitu 14 cm.

Contoh Soal Luas Dan Keliling Persegi Panjang Beserta Jawabannya

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